25x^2=37

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Solution for 25x^2=37 equation:



25x^2=37
We move all terms to the left:
25x^2-(37)=0
a = 25; b = 0; c = -37;
Δ = b2-4ac
Δ = 02-4·25·(-37)
Δ = 3700
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{3700}=\sqrt{100*37}=\sqrt{100}*\sqrt{37}=10\sqrt{37}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-10\sqrt{37}}{2*25}=\frac{0-10\sqrt{37}}{50} =-\frac{10\sqrt{37}}{50} =-\frac{\sqrt{37}}{5} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+10\sqrt{37}}{2*25}=\frac{0+10\sqrt{37}}{50} =\frac{10\sqrt{37}}{50} =\frac{\sqrt{37}}{5} $

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